Moldova National Mathematical Olympiad 2008.

Yesterday was the first day and today the second day. Here are the problems for 12th grade.

Check here for the problems in pdf format. Next week I have holiday, so I will try to upload problems for other grades, eventually with solutions.

Day 1

Problem 1

 Consider the equation x^4-4x^3+4x^2+ax+b=0, where a,b\in\mathbb{R}. Determine the largest value a+b can take, so that the given equation has two distinct positive roots x_1,x_2 so that x_1+x_2=2x_1x_2.

 Problem 2

Evaluate 

\displaystyle E=\int_0^{\frac\pi2}\cos^{1003}x\text{d}x\cdot\int_0^{\frac\pi2}\cos^{1004}x\text{d}x.

Problem 3

In the usual coordinate system xOy, line d intersects circles C_1:(x+1)^2+y^2=1 and C_2:(x-2)^2+y^2=4 in the points A,B,C,D (in this order), all having positive Oy coordinates. Given that A\left(-\frac32,\frac{\sqrt3}2\right) and m(\angle{BOC})=60^\circ find the slope of d.

Problem 4

Define the sequence (a_p)_{pge0} as follows:

a_p=\displaystyle\frac{\binom p0}{2\cdot 4}-\frac{\binom p1}{3\cdot5}+\frac{\binom p2}{4\cdot6}-\ldots+(-1)^p\cdot\frac{\binom pp}{(p+2)(p+4)}

 Compute \displaystyle\lim_{n\to\infty}(a_0+a_1+\ldots+a_n).

Day 2

Problem 5

Find the least positive integer n so that the polynomial P(X)=\sqrt3X^{n+1}-X^n-1 has at least one root of modulus 1.

Problem 6

For n\ge1, let

\displaystyle a_n=\frac1{\sqrt{n^2+8n-1}}+\frac1{\sqrt{n^2+16n-1}}+\frac1{\sqrt{n^2+24n-1}}+\ldots+\frac1{\sqrt{9n^2-1}}

Find \displaystyle\lim_{n\to\infty}a_n.

Problem 7

Vertices B,C of triangle are fixed and BC=2, while A is variable. Denote by H and G the orthocenter and centroid respectively of triangle ABC. Let F\in (HG) so that HF/FG=3. Find the locus of the point A so that F\in BC.

Problem 8

Evaluate

\displaystyle I = \int_0^{\frac\pi4}\left(\sin^62x + \cos^62x\right)\cdot \ln(1 + \tan x)\text{d}x

2 Responses

  1. is this olympiad for high school? why is there some calculus problems?

  2. That’s because we study calculus in high school and the olympiad is more or less after the curriculum.

    Sorry for the late reply.

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